To determine the exact nitrogen content of pure urea, chemists use standard percentage composition calculations. This method requires two key pieces of information:
The molecular weight of the entire urea molecule
The total atomic weight of all nitrogen atoms
The formula used is:
%Nitrogen=(total weight of nitrogen atoms ÷ molecular weight of urea) × 100
Let’s calculate using atomic weight in grams per mole (g/mol):
Nitrogen (N): 14 grams/mole
Carbon (C): 12 grams/mole
Hydrogen (H): 1 gram/mole
Oxygen (O): 16 grams/mole
Firstly, calculate the molecular weight of urea (CH ₄ N ₂ O):
Molecular weight=2 (N)+C+4 (H)+O=2 (14)+12+4 (1)+16=28+12+4+16=60 g/mol
Secondly, calculate the total weight of nitrogen atoms in a urea molecule. Because there are two nitrogen atoms:
Nitrogen weight=14+14=28 grams/mole
Finally, apply the following formula:
%Nitrogen=(28 ÷ 60) × 100=46.67%
Correct answer: Approximately 46-47%
In theory, pure urea contains approximately 46.67% nitrogen by weight. In fact, this number has been cited as 46% or 46.6% in industry standards and widely accepted chemical references.
In other words, for every 100 pounds of pure urea, only about 46-47 pounds are elemental nitrogen. The remaining 53-54 pounds are composed of carbon, hydrogen, and oxygen, none of which is elemental nitrogen. Therefore, urea is not 100% nitrogen; It contains approximately 46% nitrogen.
This calculation has been confirmed by multiple authoritative sources, including chemical databases, textbooks, and international fertilizer standards.